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Answer :
First, we note that Matt's cell phone can store up to [tex]$500$[/tex] pictures.
Since his cell phone uses [tex]$4$[/tex] picture-equivalents of memory for each second of video, we begin by converting the video duration into seconds. One minute and [tex]$30$[/tex] seconds is:
[tex]$$
1\text{ minute} + 30\text{ seconds} = 60 + 30 = 90\text{ seconds}.
$$[/tex]
The video takes up memory equivalent to:
[tex]$$
\text{Memory used by video} = 90 \times 4 = 360 \text{ picture equivalents}.
$$[/tex]
To determine the maximum number of pictures that can still be stored, subtract the memory used by the video from the total storage capacity:
[tex]$$
\text{Remaining pictures} = 500 - 360 = 140.
$$[/tex]
Thus, after recording [tex]$1$[/tex] minute and [tex]$30$[/tex] seconds of video, Matt's cell phone can store a maximum of [tex]$\boxed{140}$[/tex] pictures.
Since his cell phone uses [tex]$4$[/tex] picture-equivalents of memory for each second of video, we begin by converting the video duration into seconds. One minute and [tex]$30$[/tex] seconds is:
[tex]$$
1\text{ minute} + 30\text{ seconds} = 60 + 30 = 90\text{ seconds}.
$$[/tex]
The video takes up memory equivalent to:
[tex]$$
\text{Memory used by video} = 90 \times 4 = 360 \text{ picture equivalents}.
$$[/tex]
To determine the maximum number of pictures that can still be stored, subtract the memory used by the video from the total storage capacity:
[tex]$$
\text{Remaining pictures} = 500 - 360 = 140.
$$[/tex]
Thus, after recording [tex]$1$[/tex] minute and [tex]$30$[/tex] seconds of video, Matt's cell phone can store a maximum of [tex]$\boxed{140}$[/tex] pictures.
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