The tank in the figure has a width of 12 cm, a length of 38.8 cm, and a height of 11.8 cm. It accelerates to the right at [tex]6.3 \, \text{m/s}^2[/tex]. Determine the value of the force on panel AB after the acceleration. Note: The image refers to the tank before being accelerated.

Question

17-03-2024
Engineering

College

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The tank in the figure has a width of 12 cm, a length of 38.8 cm, and a height of 11.8 cm. It accelerates to the right at [tex]6.3 \, \text{m/s}^2[/tex]. Determine the value of the force on panel AB after the acceleration. Note: The image refers to the tank before being accelerated.

Answer :

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viivek viivek · Answer 1 · 2024-02-03T04:42:59-05:00

Final answer:

The value of the force on panel AB after the acceleration is 34.6 Newtons.

Explanation:

In order to determine the force on panel AB after acceleration, we need to know the volume of the liquid in the tank and its density. The volume of a cuboid is given by length x width x height. In this case, the volume V of the liquid would be 12cm * 38.8cm * 11.8cm = 5486.08 cubic cm.

Next, convert this volume to cubic meters by dividing by 1,000,000 (since there are 1,000,000 cubic centimeters in a cubic meter), giving us 0.00548608 m^3.

We're not given the specific liquid, but if we assume the liquid is water (density = 1000 kg/m^3), the mass m of the water in the tank would be density x volume = 1000 kg/m^3 * 0.00548608 m^3 = 5.48608 kg.

The force exerted by the water on the wall when the tank accelerates to the right is given by F = m * a, where a is the acceleration. Given an acceleration of 6.3 m/s^2, the force F = 5.48608kg * 6.3 m/s^2 = 34.582104 N. Hence, the force on panel AB is approximately 34.6 Newtons.

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