College

We appreciate your visit to The product of two consecutive negative integers is 600 What is the value of the lesser integer A 60 B 30 C 25 D 15. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

The product of two consecutive negative integers is 600. What is the value of the lesser integer?

A. -60
B. -30
C. -25
D. -15

Answer :

Final answer:

To find the lesser integer, we solve the quadratic equation x(x+1) = 600 by factoring it into (x+25)(x-24) = 0 and determine the value of x.


Explanation:

Let's assume the first integer as x. The next consecutive negative integer will be x+1. We know that the product of these two integers is 600. So, we can write the equation as x(x+1) = 600.

Expanding this equation, we get x^2 + x - 600 = 0. Now, let's factorize this quadratic equation to find the values of x.

Factoring, we can rewrite the equation as (x+25)(x-24) = 0. So, the possible values of x are -25 and 24. Since we were asked for the lesser integer, the value of the lesser integer is -25.


Learn more about Solving quadratic equations here:

https://brainly.com/question/27318739


Thanks for taking the time to read The product of two consecutive negative integers is 600 What is the value of the lesser integer A 60 B 30 C 25 D 15. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada