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\multicolumn{2}{|r|}{English System} & \multicolumn{2}{|r|}{Metric System} \\
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Problem: & How many bricks 3.75 in. wide [tex]$\times$[/tex] 8 in. long are required to cover a patio 13 ft 6 in. wide by 18 ft 9 in. long? & Problem: & How many bricks 9.5 cm wide [tex]$\times$[/tex] 20 cm long are required to cover a patio 4 meters wide by 5 meters long? \\
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Step 1. & First, find the total width and length of the patio in inches. & Step 1. & First, find the area of the patio in square cm. \\
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Step 1a. & \begin{tabular}{l}
Convert the portion of width and length that is expressed in feet to inches: \\
width: [tex]$13 \text{ ft} = 13 \times 12 = 156 \text{ in.}$[/tex] \\
length: [tex]$18 \text{ ft} = 18 \times 12 = 216 \text{ in.}$[/tex]
\end{tabular} & Step 1a. & \begin{tabular}{l}
Convert the width and length in meters to cm: \\
width: [tex]$4 \text{ m} = 4 \times 100 = 400 \text{ cm}$[/tex] \\
length: [tex]$5 \text{ m} = 5 \times 100 = 500 \text{ cm}$[/tex]
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Step 1b. & \begin{tabular}{l}
Add these values to the portion of the width and length of the patio expressed in inches to find totals: \\
total width: [tex]$156 \text{ in.} + 6 \text{ in.} = 162 \text{ in.}$[/tex] \\
total length: [tex]$216 \text{ in.} + 9 \text{ in.} = 225 \text{ in.}$[/tex]
\end{tabular} & Step 2. & \begin{tabular}{l}
Find the area of the patio in square cm by multiplying its width by its length: \\
[tex]$400 \text{ cm} \times 500 \text{ cm} = 200,000 \text{ cm}^2$[/tex]
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