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Answer :
To find the potential energy of a 25 kg bicycle resting at the top of a hill that is 3 meters high, we can use the formula for gravitational potential energy:
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
Where:
- [tex]\( m \)[/tex] is the mass (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height (in meters).
Let's break it down step by step:
1. Identify the values:
- Mass, [tex]\( m = 25 \, \text{kg} \)[/tex]
- Acceleration due to gravity, [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
- Height, [tex]\( h = 3 \, \text{m} \)[/tex]
2. Substitute these values into the formula:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
3. Calculate the result:
[tex]\[ \text{PE} = 735 \, \text{Joules} \][/tex]
The potential energy of the bicycle at the top of the hill is 735 Joules. Therefore, the correct answer is 735 J.
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
Where:
- [tex]\( m \)[/tex] is the mass (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height (in meters).
Let's break it down step by step:
1. Identify the values:
- Mass, [tex]\( m = 25 \, \text{kg} \)[/tex]
- Acceleration due to gravity, [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
- Height, [tex]\( h = 3 \, \text{m} \)[/tex]
2. Substitute these values into the formula:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
3. Calculate the result:
[tex]\[ \text{PE} = 735 \, \text{Joules} \][/tex]
The potential energy of the bicycle at the top of the hill is 735 Joules. Therefore, the correct answer is 735 J.
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