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Answer :
We start with the formula that relates the speed of light, frequency, and wavelength:
[tex]$$
\lambda = \frac{c}{f}
$$[/tex]
where
- [tex]$\lambda$[/tex] is the wavelength (in meters),
- [tex]$c$[/tex] is the speed of light ([tex]$3 \times 10^8 \, \text{m/s}$[/tex]),
- [tex]$f$[/tex] is the frequency (in Hz).
Given the frequency is
[tex]$$
f = 99.7 \times 10^6 \, \text{Hz},
$$[/tex]
we substitute the known values into the formula:
[tex]$$
\lambda = \frac{3 \times 10^8 \, \text{m/s}}{99.7 \times 10^6 \, \text{Hz}}.
$$[/tex]
To simplify the calculation, first notice that
[tex]$$
\frac{3 \times 10^8}{99.7 \times 10^6} = \frac{3}{99.7} \times \frac{10^8}{10^6} = \frac{3}{99.7} \times 10^2.
$$[/tex]
Calculating the fraction [tex]$\frac{3}{99.7}$[/tex] gives approximately [tex]$0.03009$[/tex]. Multiplying by [tex]$10^2$[/tex] (or 100):
[tex]$$
\lambda \approx 0.03009 \times 100 = 3.009 \, \text{meters}.
$$[/tex]
Thus, the wavelength of the radio waves is approximately
[tex]$$
3.009 \, \text{meters}.
$$[/tex]
[tex]$$
\lambda = \frac{c}{f}
$$[/tex]
where
- [tex]$\lambda$[/tex] is the wavelength (in meters),
- [tex]$c$[/tex] is the speed of light ([tex]$3 \times 10^8 \, \text{m/s}$[/tex]),
- [tex]$f$[/tex] is the frequency (in Hz).
Given the frequency is
[tex]$$
f = 99.7 \times 10^6 \, \text{Hz},
$$[/tex]
we substitute the known values into the formula:
[tex]$$
\lambda = \frac{3 \times 10^8 \, \text{m/s}}{99.7 \times 10^6 \, \text{Hz}}.
$$[/tex]
To simplify the calculation, first notice that
[tex]$$
\frac{3 \times 10^8}{99.7 \times 10^6} = \frac{3}{99.7} \times \frac{10^8}{10^6} = \frac{3}{99.7} \times 10^2.
$$[/tex]
Calculating the fraction [tex]$\frac{3}{99.7}$[/tex] gives approximately [tex]$0.03009$[/tex]. Multiplying by [tex]$10^2$[/tex] (or 100):
[tex]$$
\lambda \approx 0.03009 \times 100 = 3.009 \, \text{meters}.
$$[/tex]
Thus, the wavelength of the radio waves is approximately
[tex]$$
3.009 \, \text{meters}.
$$[/tex]
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