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Answer :
Answer:
the force B is less than the maximum force consequently Boat B floats
Explanation:
To solve this exercise let's use the pressure defined
P = [tex]\frac{F}{A}[/tex]
F = P A
let's start for boat A
let's search the area
A = l a
A₁ = 45 126
A₁ = 5670 m²
the force applied by this ship is
F₁ = 2300 5670
F₁ = 1.3 10⁷ N
now we do the calculation for ship B
A₂ = 6 115
A₂ = 690 m²
F₂ = P₂ A₂
F₂ = 2700 690
F₂ = 1.8 10⁶ N
indicate that the force should not be greater than F₀ = 2.0 10⁶ N, let's look for the relationship with each one
[tex]\frac{F_1}{F_0}[/tex] = 1.3 10⁷/2 10⁶
F₁ = 6.5 F₀
This force is greater than the one that can resist therefore the ship and sinks
[tex]\frac{F_2}{F_o}[/tex] = 1.8 /2
F₂ = 0.9 F₀
therefore this force is less than the maximum force consequently Boat B floats
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