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Answer :
Answer:
a)115 N
b)For father acceleration = 1.69 m/s²
For son acceleration = 3.28 m/s²
Explanation:
Given that
Mass of man(M)= 68 kg
Mass of son (m)= 34 kg
F= 115 N
As we know that from third law of Newtons ,It sates that every action have it reaction in opposite direction but same in magnitude.
So the force exerted by boy on father = 115 N
From Newtons second law of motion
F= m a
F=Force
m= mass
a=acceleration
For father
115 = 68 x a
a=1.69 m/s²
For son
115 = 35 x a'
a'=3.28 m/s²
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Final answer:
The force exerted by the boy on his father is 115 N, following Newton's Third Law of Motion. The father accelerates at 1.69 m/s² and the son at 3.38 m/s² due to their difference in mass, as described by Newton's Second Law of Motion.
Explanation:
The question revolves around the concept of Newton's Third Law of Motion and the comparison of accelerations between two masses. Specifically, it focuses on an 68 kg man on ice skates pushing his 34 kg son, also on ice skates, with a force of 115 N across the ice. According to Newton's Third Law, for every action, there is an equal and opposite reaction. Thus, the force exerted by the boy on his father is also 115 N, but in the opposite direction.
To compare the magnitudes of the two accelerations, you use Newton's Second Law of Motion (F = ma). The father's acceleration can be calculated using a = F/m, where F is the net force applied (115 N, considering only the force of pushing without accounting for external forces like friction since they move steadily gaining speed), and m is the mass of the father. Similarly, the son's acceleration is calculated using the same formula.
For the father: a = 115 N / 68 kg = 1.69 m/s².
For the son: a = 115 N / 34 kg = 3.38 m/s².
Therefore, the accelerations are different due to the mass difference, with the son experiencing a higher acceleration as a result of having half the mass of his father.
