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What is the force acting on an object that goes from 5 m/s to 20 m/s in 3 seconds and has a mass of 52 kg?

A. 156 N
B. 1300 N
C. 1040 N
D. 260 N

Answer :

Final answer:

To calculate the force acting on an object that changes velocity over time, we can use Newton's second law of motion, F = m * a. By plugging in the given values for initial velocity, final velocity, time, and mass, we find that the force acting on the object is 260 N.


Explanation:

To calculate the force acting on an object, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a). In this case, the object's initial velocity (u) is 5 m/s, final velocity (v) is 20 m/s, and time (t) is 3 seconds. The change in velocity (Δv) is v - u = 20 m/s - 5 m/s = 15 m/s. We can then calculate the acceleration (a) using the equation a = Δv / t = 15 m/s / 3 s = 5 m/s².

Now, we can calculate the force (F) using the equation F = m * a. The mass (m) is given as 52 kg. Substituting the values, we have F = 52 kg * 5 m/s² = 260 N. Therefore, the force acting on the object is 260 N.


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