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A toy rocket is shot vertically into the air from a launching pad 9 feet above the ground with an initial velocity of 48 feet per second. The height [tex] h [/tex], in feet, of the rocket above the ground at [tex] t [/tex] seconds after launch is given by the function [tex] h(t) = -16t^2 + 48t + 9 [/tex].

1. How long will it take the rocket to reach its maximum height?
2. What is the maximum height?

Answer :

To find out how long it takes for the toy rocket to reach its maximum height and what that height is, we need to analyze the height function of the rocket:

[tex]\[ h(t) = -16t^2 + 48t + 9 \][/tex]

This function is a quadratic equation, where:
- The coefficient of [tex]\(t^2\)[/tex] is [tex]\(a = -16\)[/tex],
- The coefficient of [tex]\(t\)[/tex] is [tex]\(b = 48\)[/tex],
- The constant term is [tex]\(c = 9\)[/tex].

### Finding the Time of Maximum Height

For any quadratic function in the form [tex]\(ax^2 + bx + c\)[/tex], the maximum or minimum value occurs at [tex]\(t = -\frac{b}{2a}\)[/tex]. This is known as the vertex formula for parabolas.

Plugging in our values:
- [tex]\(a = -16\)[/tex],
- [tex]\(b = 48\)[/tex].

The time [tex]\(t\)[/tex] when the rocket reaches its maximum height is:

[tex]\[ t = -\frac{48}{2 \times (-16)} \][/tex]

[tex]\[ t = -\frac{48}{-32} \][/tex]

[tex]\[ t = 1.5 \][/tex]

So, it takes 1.5 seconds for the rocket to reach its maximum height.

### Calculating the Maximum Height

Once we have the time at which the maximum height occurs, we substitute [tex]\(t = 1.5\)[/tex] back into the height function to find the maximum height:

[tex]\[ h(1.5) = -16(1.5)^2 + 48(1.5) + 9 \][/tex]

[tex]\[ h(1.5) = -16(2.25) + 72 + 9 \][/tex]

[tex]\[ h(1.5) = -36 + 72 + 9 \][/tex]

[tex]\[ h(1.5) = 45 \][/tex]

Therefore, the maximum height reached by the rocket is 45 feet.

In summary:
- The rocket reaches its maximum height after 1.5 seconds.
- The maximum height of the rocket is 45 feet.

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Rewritten by : Barada