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A patient requires potassium chloride 25 meq in a 1000 ml bag of lactated Ringer's solution. The pharmacy has on hand potassium chloride for injection 40 meq in 20 ml vials. How many milliliters will be needed in the IV bag?

Answer :

To provide the desired 25 meq dose of potassium chloride in the IV bag, 12.5 ml of the stock solution (40 meq in 20ml vial) is required.

The pharmacy has on hand potassium chloride for injection at a concentration of 40 meq in 20 ml vials. To prepare a solution containing 25 meq of potassium chloride in a 1000 ml IV bag, you need to perform a dilution calculation.

Since one vial contains 40 meq, and we only need 25 meq, we need to determine the proportion of the vial to use:

V1 (volume from vial needed) = (25 meq needed) / (40 meq available per vial) x (Volume of vial)

V1 = (25/40) x 20 ml

V1 = 0.625 x 20 ml

V1 = 12.5 ml

Therefore, 12.5 ml of the stock potassium chloride solution should be drawn up and added to the IV bag of lactated ringers solution in order to achieve the required 25 meq potassium chloride dosage for the patient.

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Rewritten by : Barada

To prepare a 1000 ml bag of lactated Ringer's solution with potassium chloride 25 meq, 50 ml of potassium chloride for injection 40 meq in 32 ml vials will be needed.

To prepare a 1000 ml bag of lactated Ringer's solution with potassium chloride 25 meq, 50 ml of potassium chloride for injection 40 meq in 20 ml vials will be needed.

First, determine the concentration of potassium chloride needed in the final IV bag. Since the desired concentration is 25 meq in 1000 ml, use the formula:

Concentration = Total amount of potassium chloride (meq) / Total volume of IV solution (ml)

Substitute the values:

25 meq = x meq / 1000 ml

Solve for x:

x = 25 * 1000 = 25000 meq/ml

Next, determine how much of the concentrated potassium chloride solution is needed. Since each vial contains 40 meq in 20 ml, calculate the volume required using the formula:

Volume (ml) = Total amount of potassium chloride needed (meq) / Concentration of potassium chloride in vial (meq/ml)

Substitute the values:

Volume (ml) = 25000 meq / 40 meq/ml

Solve for the volume:

Volume (ml) = 25000 / 40 = 625 ml

However, since each vial contains 20 ml, we need to divide the total volume required by 20 ml to find out how many vials are needed:

Number of vials = Volume (ml) / Volume per vial (ml) = 625 ml / 20 ml/vial = 31.25

Since we cannot have a fraction of a vial, we need to round up to the nearest whole number. Therefore, 32 vials are required.