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Answer :
4.3 x 10^21 molecules of UF6 weigh approximately **2.51 grams**.
Here's how to calculate the mass of 4.3 x 10^21 molecules of UF6:
**1. Determine the molar mass of UF6:**
- Uranium (U): 238.03 g/mol
- Fluorine (F): 18.998 g/mol
- UF6 contains one U atom and six F atoms, so its molar mass is:
- 238.03 g/mol (U) + 6 * 18.998 g/mol (F) ≈ 352.04 g/mol
**2. Calculate the number of moles in 4.3 x 10^21 molecules:**
- Avogadro's number is approximately 6.022 x 10^23 molecules/mol.
- We can use the following formula:
- Number of moles = Number of molecules / Avogadro's number
- Number of moles = 4.3 x 10^21 molecules / 6.022 x 10^23 molecules/mol ≈ 7.13 x 10^-3 mol
**3. Calculate the mass of 4.3 x 10^21 molecules:**
- Mass = Number of moles * Molar mass
- Mass = 7.13 x 10^-3 mol * 352.04 g/mol ≈ 2.51 g
Therefore, 4.3 x 10^21 molecules of UF6 weigh approximately **2.51 grams**.
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