We appreciate your visit to For each situation determine whether to use a permutation or a combination Then solve the problem 16 How many different orders can you choose to. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The problems require determining whether to use combinations or permutations based on whether the order of selection matters. Examples show how to calculate the number of ways to select items in various scenarios, leading to correct total values for each situation.
Explanation:
Analysis of Combinations and Permutations
In this set of problems, we determine whether to use permutations or combinations based on the context of the question. A permutation is used when the order of selection matters, while a combination is used when the order does not matter.
Problem 16: Different Orders of Reading Books
Since the order in which you read the books matters, we use permutations. The number of permutations of selecting 6 books from 9 is calculated as: P(9, 6) = 9! / (9-6)! = 9! / 3! = 9 × 8 × 7 × 6 × 5 × 4 = 60480.
Problem 17: Choosing Shirts
Here, the order does not matter, so we use combinations. The number of combinations to choose 5 shirts out of 7 is calculated as: C(7, 5) = 7! / [5! × (7-5)!] = 21.
Problem 18: Choosing Flowers
Similar to the previous problem, order does not matter, so we use combinations. The number of ways to choose 2 out of 4 flowers is: C(4, 2) = 4! / [2! × (4-2)!] = 6.
Problem 19: Five-Person Committees
Again, the order does not matter, leading us to use combinations. The number of 5-person committees from a group of 12 people is: C(12, 5) = 792.
Problem 20: Seniors and Juniors
Since the order does not matter, we apply combinations. The number of ways to choose 3 seniors from 6 and 2 juniors from 8 is given by: C(6, 3) × C(8, 2) = 20 × 28 = 560.
Problem 21: Choosing Multiple Choice Questions
Here, the order does not matter, so we use combinations. The number of ways to select 12 questions out of 15 is: C(15, 12) = C(15, 3) = 455.
Problem 22: Three-Digit Identification Code
Since no digit can be repeated, the order matters, thus we use permutations. The greatest number of subjects that can be coded is: P(10, 3) = 10 × 9 × 8 = 720.
Problem 23: Pizzeria Otto's Toppings
This is a combination problem because the order of toppings does not matter, and pizzas must have at least one topping. The total combinations can be calculated using the formula: 2^8 - 1 = 255, where 2^8 represents all combinations including no toppings.
Learn more about Combinations and Permutations here:
https://brainly.com/question/3901018
Thanks for taking the time to read For each situation determine whether to use a permutation or a combination Then solve the problem 16 How many different orders can you choose to. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada