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Answer :
To find the potential energy of a 25 kg bicycle at the top of a 3 m high hill, we use the formula for potential energy:
[tex]\[ PE = m \cdot g \cdot h \][/tex]
Where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass in kilograms,
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex],
- [tex]\( h \)[/tex] is the height in meters.
Let's plug in the values:
1. The mass [tex]\( m = 25 \, \text{kg} \)[/tex].
2. The acceleration due to gravity [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex].
3. The height [tex]\( h = 3 \, \text{m} \)[/tex].
Now, calculate the potential energy:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle is 735 Joules.
[tex]\[ PE = m \cdot g \cdot h \][/tex]
Where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass in kilograms,
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex],
- [tex]\( h \)[/tex] is the height in meters.
Let's plug in the values:
1. The mass [tex]\( m = 25 \, \text{kg} \)[/tex].
2. The acceleration due to gravity [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex].
3. The height [tex]\( h = 3 \, \text{m} \)[/tex].
Now, calculate the potential energy:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle is 735 Joules.
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