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What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high? (Formula: [tex]PE = mgh[/tex])

A. 75 J
B. 735 J
C. 245 J
D. 37.8 J

Answer :

To find the potential energy of a bicycle resting at the top of a hill, we use the formula for potential energy:

[tex]\[ PE = m \times g \times h \][/tex]

where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (in meters per second squared),
- [tex]\( h \)[/tex] is the height of the object above the ground (in meters).

For this problem:
- The mass [tex]\( m \)[/tex] of the bicycle is 25 kg,
- The height [tex]\( h \)[/tex] of the hill is 3 m,
- The standard acceleration due to gravity [tex]\( g \)[/tex] is approximately 9.8 m/s².

Let's plug these values into the formula:

[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]

Calculating step-by-step:
1. Multiply the mass (25 kg) by the acceleration due to gravity (9.8 m/s²):
[tex]\[ 25 \times 9.8 = 245 \][/tex]

2. Then, multiply the result by the height (3 m):
[tex]\[ 245 \times 3 = 735 \][/tex]

Therefore, the potential energy of the bicycle at the top of the hill is 735 joules. So, the correct answer is 735 J.

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