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Answer :
The sample of the unknown metal has the mass of the 135 grams. The sample cools from the 100.5 °C to the 35.5 °C, and it releases the 7500 joules of the energy. The specific heat of the sample is 0.854 J/g °C.
Th mass of the metal = 135 g
The initial temperature = 100.5 °C
The final temperature = 35.5 °C
The heat energy releases = - 7500 J
The heat energy is expressed as :
Q = mc ΔT
Where,
The m is mass of the metal = 135 g
The c is the specific heat capacity = ?
The Q is heat energy releases = - 7500 J
The ΔT is the change in the temperature = final temperature - initial temperature.
The ΔT is the change in the temperature = 35.5 - 100.5
The ΔT is the change in the temperature = - 65 °C
The specific heat capacity, c = Q / m ΔT
The specific heat capacity, c = - 7500 / 135 × - 65
The specific heat capacity, c = 0.854 J/g °C
The specific heat capacity of metal is 0.854 J/g °C.
To learn more about specific heat here
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