College

We appreciate your visit to Water flows uniformly at a depth of 1 2 m 4 ft in a rectangular canal 3 m 10 ft wide laid on a slope. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Water flows uniformly at a depth of 1.2 m (4 ft) in a rectangular canal 3 m (10 ft) wide, laid on a slope of 1 m per 1,000 m (1 ft per 1,000 ft). What is the mean shear stress on the sides and bottom of the canal?

Answer :

The mean shear stress on the sides and bottom of the canal can be calculated using the concept of fluid mechanics and the principles of open channel flow. In open channel flow, the shear stress is caused by the friction between the flowing water and the boundary surfaces of the channel.

The mean shear stress on the sides and bottom of the canal can be determined using Manning's equation, which relates the shear stress to the hydraulic radius and the channel slope. Manning's equation is as follows:

width (b) = 3m

depth (9) = 1.2m

slope =1.2m

1000

mean sheep stress = 3m

=9870

So

=

3. R. So

1000

A = bxy = 1.2x3

P = b+2y

R = A Р

1.2x3

3+2(1.2)

8.R.So

Zmean

=

=

=

= 0.67

(1/0)

1000

(9870) (0.67) (

=

6.54 KN/m2

3+ 2(1.2)

Learn more about shear stress here

https://brainly.com/question/28579412

#SPJ4

Thanks for taking the time to read Water flows uniformly at a depth of 1 2 m 4 ft in a rectangular canal 3 m 10 ft wide laid on a slope. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada