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Answer :
The cross between a heterozygous white-fruited squash plant and a yellow-fruited plant results in genotypes 1/2 Ww and 1/2 ww, and phenotypes 1/2 white and 1/2 yellow in a 1:1 ratio. The correct option is 2.
To address this question, we need to analyze the cross between a heterozygous white-fruited squash plant (Ww) and a yellow-fruited squash plant (ww). Here, W (white) is dominant over w (yellow).
Using a Punnett square, we can determine the possible genotypes and phenotypes of the offspring:
Genotypes and Phenotypes:
- Genotypes: 1/2 Ww, 1/2 ww (1:1 ratio)
- Phenotypes: 1/2 white, 1/2 yellow (1:1 ratio)
The correct answer is option 2 as it accurately represents the expected outcomes of this cross.
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Answer:
2. Genotypes 1/2 Ww 1/2 ww 1:1 ratio | Phenotypes 1/2 white 1/2 yellow 1:1 ratio
Explanation:
This question involves a single gene coding for fruit color in squash. The allele for white color (W) is dominant over the allele for yellow color (w).
If a heterozygous white-fruited plant (Ww) is crossed with a yellow-fruited plant (ww), the following gamete combinations will be produced by each parent:
Ww- W and w
ww- w and w
Using these gametes in a punnet square (see attached image), offsprings with genotypes: Ww and ww will be produced in the ratio 1:1
(1/2) Ww will be phenotypically white-fruited
(1/2) ww will be phenotypically yellow-fruited
Hence, the seed offsprings of this cross will possess:
Genotypes 1/2 Ww, 1/2 ww in 1:1 ratio
Phenotypes 1/2 white, 1/2 yellow in 1:1 ratio
