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The area of a rectangular pool is 120 square feet. The width of the pool is [tex]x[/tex] feet. Solve the equation [tex]x^2 + 2x - 120 = 0[/tex] to find the value of [tex]x[/tex], the width of the pool.

A. 12 feet
B. 8 feet
C. 10 feet
D. -12 feet

Answer :

To find the width of the pool, we need to solve the quadratic equation [tex]\(x^2 + 2x - 120 = 0\)[/tex].

Step 1: Identify the coefficients

The quadratic equation is in the standard form [tex]\(ax^2 + bx + c = 0\)[/tex]. From the equation:

- [tex]\(a = 1\)[/tex]
- [tex]\(b = 2\)[/tex]
- [tex]\(c = -120\)[/tex]

Step 2: Calculate the discriminant

The discriminant ([tex]\(D\)[/tex]) of a quadratic equation [tex]\(ax^2 + bx + c = 0\)[/tex] is given by:

[tex]\[D = b^2 - 4ac\][/tex]

Plugging in the values:

[tex]\[D = 2^2 - 4 \times 1 \times (-120)\][/tex]
[tex]\[D = 4 + 480\][/tex]
[tex]\[D = 484\][/tex]

Step 3: Solve for the roots

The roots of the quadratic equation can be calculated using the quadratic formula:

[tex]\[x = \frac{-b \pm \sqrt{D}}{2a}\][/tex]

With our values:

[tex]\[x = \frac{-2 \pm \sqrt{484}}{2 \times 1}\][/tex]

Step 4: Calculate the two possible solutions

Since [tex]\(\sqrt{484} = 22\)[/tex], we find the roots:

- [tex]\(x_1 = \frac{-2 + 22}{2} = \frac{20}{2} = 10\)[/tex]
- [tex]\(x_2 = \frac{-2 - 22}{2} = \frac{-24}{2} = -12\)[/tex]

Step 5: Choose the positive root

Since the width of the pool cannot be negative, the valid solution is the positive root:

- The width of the pool, [tex]\(x\)[/tex], is 10 feet.

Therefore, the value of [tex]\(x\)[/tex], the width of the pool, is [tex]\(10\)[/tex] feet.

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