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Answer :
Let's divide the given binary numbers step by step:
1. Divide [tex]\( 1001_2 \)[/tex] by [tex]\( 11_2 \)[/tex]:
- Convert the binary numbers to decimals:
- [tex]\( 1001_2 \)[/tex] is [tex]\( 1 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 8 + 0 + 0 + 1 = 9 \)[/tex].
- [tex]\( 11_2 \)[/tex] is [tex]\( 1 \times 2^1 + 1 \times 2^0 = 2 + 1 = 3 \)[/tex].
- Now, divide 9 by 3:
- [tex]\( 9 \div 3 = 3 \)[/tex].
2. Divide [tex]\( 11010_2 \)[/tex] by [tex]\( 10_2 \)[/tex]:
- Convert the binary numbers to decimals:
- [tex]\( 11010_2 \)[/tex] is [tex]\( 1 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 = 16 + 8 + 0 + 2 + 0 = 26 \)[/tex].
- [tex]\( 10_2 \)[/tex] is [tex]\( 1 \times 2^1 + 0 \times 2^0 = 2 \)[/tex].
- Now, divide 26 by 2:
- [tex]\( 26 \div 2 = 13 \)[/tex].
3. Divide [tex]\( 11001_2 \)[/tex] by [tex]\( 101_2 \)[/tex]:
- Convert the binary numbers to decimals:
- [tex]\( 11001_2 \)[/tex] is [tex]\( 1 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 16 + 8 + 0 + 0 + 1 = 25 \)[/tex].
- [tex]\( 101_2 \)[/tex] is [tex]\( 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 4 + 0 + 1 = 5 \)[/tex].
- Now, divide 25 by 5:
- [tex]\( 25 \div 5 = 5 \)[/tex].
4. Divide [tex]\( 1_2 \)[/tex] by [tex]\( 1_2 \)[/tex]:
- Convert the binary numbers to decimals:
- [tex]\( 1_2 \)[/tex] is [tex]\( 1 \)[/tex].
- Now, divide 1 by 1:
- [tex]\( 1 \div 1 = 1 \)[/tex].
Therefore, the results of the divisions are: [tex]\(3, 13, 5, \)[/tex] and [tex]\(1\)[/tex].
1. Divide [tex]\( 1001_2 \)[/tex] by [tex]\( 11_2 \)[/tex]:
- Convert the binary numbers to decimals:
- [tex]\( 1001_2 \)[/tex] is [tex]\( 1 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 8 + 0 + 0 + 1 = 9 \)[/tex].
- [tex]\( 11_2 \)[/tex] is [tex]\( 1 \times 2^1 + 1 \times 2^0 = 2 + 1 = 3 \)[/tex].
- Now, divide 9 by 3:
- [tex]\( 9 \div 3 = 3 \)[/tex].
2. Divide [tex]\( 11010_2 \)[/tex] by [tex]\( 10_2 \)[/tex]:
- Convert the binary numbers to decimals:
- [tex]\( 11010_2 \)[/tex] is [tex]\( 1 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 = 16 + 8 + 0 + 2 + 0 = 26 \)[/tex].
- [tex]\( 10_2 \)[/tex] is [tex]\( 1 \times 2^1 + 0 \times 2^0 = 2 \)[/tex].
- Now, divide 26 by 2:
- [tex]\( 26 \div 2 = 13 \)[/tex].
3. Divide [tex]\( 11001_2 \)[/tex] by [tex]\( 101_2 \)[/tex]:
- Convert the binary numbers to decimals:
- [tex]\( 11001_2 \)[/tex] is [tex]\( 1 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 16 + 8 + 0 + 0 + 1 = 25 \)[/tex].
- [tex]\( 101_2 \)[/tex] is [tex]\( 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 4 + 0 + 1 = 5 \)[/tex].
- Now, divide 25 by 5:
- [tex]\( 25 \div 5 = 5 \)[/tex].
4. Divide [tex]\( 1_2 \)[/tex] by [tex]\( 1_2 \)[/tex]:
- Convert the binary numbers to decimals:
- [tex]\( 1_2 \)[/tex] is [tex]\( 1 \)[/tex].
- Now, divide 1 by 1:
- [tex]\( 1 \div 1 = 1 \)[/tex].
Therefore, the results of the divisions are: [tex]\(3, 13, 5, \)[/tex] and [tex]\(1\)[/tex].
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