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The mutual inductance between two coils is [tex]170 \, \text{mH}[/tex]. Find the magnitude of the electromotive force (e.m.f.) induced in one coil when the current in the other is increasing at a rate of [tex]40 \, \text{A/s}[/tex].

Answer :

The magnitude of the e.m.f induced in one coil when the current in the other is increasing at a rate of 40 A/s is 6.8 V.


Mutual inductance is a property of two coils that are in close proximity to each other. It measures the amount of magnetic flux that is linked between the two coils. The mutual inductance between two coils is denoted by the symbol M and is measured in henries (H).

According to Faraday's law of electromagnetic induction, an e.m.f is induced in a coil whenever there is a change in the magnetic flux that links the coil. The magnitude of the induced e.m.f is given by the formula:
e = -M(dI/dt)
where e is the induced e.m.f, M is the mutual inductance, and dI/dt is the rate of change of current in the other coil.
Substituting the given values, we get:
e = -170 x 10^-3 H x (40 A/s) = -6.8 V

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