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The function [tex]$f(t) = 349.2(0.98)^t$[/tex] models the relationship between [tex]$t$[/tex], the time an oven spends cooling, and the temperature of the oven.

Oven Cooling Time

[tex]\[

\begin{tabular}{|c|c|}

\hline

\begin{tabular}{c}

Time \\

(minutes) \\

$t$

\end{tabular} &

\begin{tabular}{c}

Oven temperature \\

(degrees Fahrenheit) \\

$f(t)$

\end{tabular} \\

\hline

5 & 315 \\

\hline

10 & 285 \\

\hline

15 & 260 \\

\hline

20 & 235 \\

\hline

25 & 210 \\

\hline

\end{tabular}

\][/tex]

For which temperature will the model most accurately predict the time spent cooling?

A. 0

B. 100

C. 300

D. 400

Answer :

We are given the model

[tex]$$
f(t) = 349.2 \cdot (0.98)^t,
$$[/tex]

which relates the cooling time [tex]$t$[/tex] to the oven temperature [tex]$f(t)$[/tex]. The table below shows measured temperatures at various times:

[tex]\[
\begin{array}{|c|c|}
\hline
t \ (\text{minutes}) & f(t) \ (\text{degrees Fahrenheit}) \\ \hline
5 & 315 \\ \hline
10 & 285 \\ \hline
15 & 260 \\ \hline
20 & 235 \\ \hline
25 & 210 \\ \hline
\end{array}
\][/tex]

The measured temperatures range from a maximum of [tex]$315^\circ\text{F}$[/tex] to a minimum of [tex]$210^\circ\text{F}$[/tex]. The model will give the most reliable predictions when the temperature is within this interval because the model is based on these values.

We are asked to choose the temperature for which the model most accurately predicts the time spent cooling from these choices: [tex]$0^\circ\text{F}$[/tex], [tex]$100^\circ\text{F}$[/tex], [tex]$300^\circ\text{F}$[/tex], and [tex]$400^\circ\text{F}$[/tex].

Since [tex]$300^\circ\text{F}$[/tex] lies between [tex]$210^\circ\text{F}$[/tex] and [tex]$315^\circ\text{F}$[/tex], it is the temperature within the range of the measured data. Thus, the model will most accurately predict the cooling time for a temperature of

[tex]$$
300^\circ\text{F}.
$$[/tex]

So, the answer is [tex]$\boxed{300}$[/tex].

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