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Which runner has greater kinetic energy: a 45 kg runner moving at a speed of 7 m/s or a 93 kg runner moving at a speed of 3 m/s?

Answer :

Kinetic Energy = (1/2) (mass) (speed)

First runner: KE = (1/2) (45kg) (49 m/s) = 1,102.5 Joules

Second runner: KE = (1/2) (93kg) (9 m/s) = 418.5 Joules

The first runner has 163% more kinetic energy than the second runner has.

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Rewritten by : Barada

Final answer:

The 45 kg runner moving at 7 m/s has greater kinetic energy (1575.5 joules) compared to the 93 kg runner moving at 3 m/s (418.5 joules), as calculated by the kinetic energy formula, KE = ½ mv2.

Explanation:

To determine which runner has greater kinetic energy, we need to use the kinetic energy formula: KE = ½ mv2, where m is the mass in kilograms and v is the speed in meters per second.

For the 45 kg runner moving at 7 m/s, the kinetic energy is:

KE = ½ × 45 kg × (7 m/s)2
= ½ × 45 kg × 49 m2/s2
= 1,575.5 joules

For the 93 kg runner moving at 3 m/s, the kinetic energy is:

KE = ½ × 93 kg × (3 m/s)2
= ½ × 93 kg × 9 m2/s2
= 418.5 joules

Comparing these two values, the 45 kg runner has the greater kinetic energy.