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2-in-1 Parenteral Nutrition Order:

- Dextrose: 370 grams
- Amino acids: 105 grams
- Sodium chloride: 32 mEq
- Sodium acetate: 12 mEq
- Potassium: 65 mEq
- Magnesium sulfate: 10 mEq
- Phosphate: 24 mmol
- Calcium: 12 mEq
- Multivitamins (MVI): 10 mL
- Trace elements: 1 mL
- Famotidine: 10 mg
- Sterile water: qs ad 2000 mL

The pharmacist preparing the 2-in-1 PN uses potassium phosphate vials (3 mmol of phosphate and 4.4 mEq of potassium per mL) to add the phosphate to the PN. How many milliequivalents of potassium are added to the PN when the phosphate is added?

A. 8
B. 15
C. 24
D. 35
E. 65

Answer :

Final answer:

When potassium phosphate is used to provide 24 mmol of phosphate to the PN solution, 35 mEq of potassium is also added as a result of using 8 mL of potassium phosphate solution with 4.4 mEq of potassium per mL.

Explanation:

The student is inquiring about how many milliequivalents (mEq) of potassium are added to the parenteral nutrition (PN) when potassium phosphate is used to supply phosphate. Each mL of potassium phosphate solution contributes 3 mmol of phosphate and 4.4 mEq of potassium. The total amount of phosphate needed is 24 mmol. Since each mL provides 3 mmol, you would need 24 mmol / 3 mmol/mL = 8 mL of the potassium phosphate solution. To find the total mEq of potassium added, you would multiply the volume of potassium phosphate solution by the mEq of potassium per mL:

8 mL × 4.4 mEq/mL = 35.2 mEq of potassium

Since we are looking for the nearest whole number, it would be 35 mEq. Therefore, the correct answer is D. 35.

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