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Answer :
Mean is 121.4, standard ,the deviation is 13. 21, variance is 175.47, minimum is 95, median is 118.
Here is an estimate of the order of a given intelligence level:
a. mean (normal):
mean can be found by including all scores and dividing by the number of scores:
mean = (141 + 139 + 126 + 122 + 125 + 130 + 95 + 110 + 118 + 118)/10 = 121.4
center:
b. median
if the scores are ordered ascending, center is the center score:
95, 110 , 118, 118, 122 , 125, 126, 130, 139, 141
Median = 118
c. Standard Deviation:
The standard deviation indicates how spread out the information is. Here's a recipe for finding the standard deviation:
Standard Deviation = sqrt(Variance)
d. Variation:
Variation is the proportion of variation in the set of information. The recipe for determining the change is:
Variance = (amount of ((each score - average)^2)/(number of scores - 1)
connect the numbers obtained:
Variance = (( ( amount of each score - ) 121.4)^2)/(10 - 1)
Variance = 1579.
24/9 = 175.47
standard deviation = sqrt(variance) = sqrt(175.47) = 13.21
e. minimum:
base is information gathering minimum:
minimum = 95
so, mean is 121.4, standard The deviation is 13. 21, difference is 175.47, base is 95, middle is 118
To learn more about statistics and probability, refer:
https://brainly.com/question/26146867
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The complete question is:
Below are the iq test scores of 10 randomly chosen fifth-grade students. 141 139 126 122 125 130 95 110 118 118. calculate a. mean b. median c. standard deviation d. variance e. minimum.
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