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Answer :
Answer:
F = 88.88[lb-f]
Explanation:
To solve this problem, we must first look at the attached image.
Another important data that is needed to solve the problem is the distance from the Centre O to points C and D. The distance is 0.9 [ft].
Then we do a sum of moments around Point O and it equals zero.
[tex]SM_{O} =0\\F*0.9+F*0.9-160=0\\2*F*0.9=160\\F=88.88[lb-f][/tex]
Therefrore the couple of forces needed are 88.88[lb-f]
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