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Answer :
Final answer:
A quartic function with the given real zeroes is f(x) = x^2 - 6x + 5.
Explanation:
A quartic function is a function of the form f(x) = ax^4 + bx^3 + cx^2 + dx + e where a, b, c, d, and e are constants.
Given that the real zeroes of the function are x = 5 and x = 1, we can write the factors of the function as (x - 5) and (x - 1). To find the quartic function, we can multiply these factors together:
f(x) = (x - 5)(x - 1)
Expanding this using the distributive property, we get:
f(x) = x^2 - 6x + 5
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