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Select the correct answer from each drop-down menu.

If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a 50% chance that the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is 0%.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Answer :

Sure! Let's go through the solution step-by-step for both scenarios presented in the question.

### Scenario 1: Heterozygous Male ([tex]$Ww$[/tex]) with Homozygous Recessive Female ([tex]$ww$[/tex])

When a heterozygous male ([tex]$Ww$[/tex]) is mated with a homozygous recessive female ([tex]$ww$[/tex]), we can use a Punnett square to determine the possible genotypes of the offspring.

- Male Gametes (sperm): W or w
- Female Gametes (eggs): w or w

Now let's fill in the Punnett square:

```
w w
-----------------
W | Ww | Ww |
-----------------
w | ww | ww |
-----------------
```

From this Punnett square, the possible genotypes for the offspring are:
- Two Ww (heterozygous)
- Two ww (homozygous recessive)

Probability of Heterozygous ([tex]$Ww$[/tex]) Offspring:

There are 2 instances of Ww out of a total of 4 possible outcomes. So, the probability of having a heterozygous (Ww) offspring is:

[tex]\[ \text{Probability} = \frac{2}{4} = 0.5 \][/tex]

### Scenario 2: Heterozygous ([tex]$Ww$[/tex]) with Homozygous Dominant ([tex]$WW$[/tex])

In this case, a heterozygous (Ww) individual is crossed with a homozygous dominant (WW) individual.

- First Parent (Ww):
- Gametes: W or w
- Second Parent (WW):
- Gametes: W or W

Let's fill in the Punnett square:

```
W W
-----------------
W | WW | WW |
-----------------
w | Ww | Ww |
-----------------
```

The possible genotypes for the offspring are:
- Two WW (homozygous dominant)
- Two Ww (heterozygous)

Probability of Homozygous Recessive (ww) Offspring:

None of the offspring can be homozygous recessive (ww) because all possible genotypes contain at least one dominant W allele. So, the probability of having a homozygous recessive (ww) offspring is:

[tex]\[ \text{Probability} = 0 \][/tex]

I hope this breakdown helps you understand how these probabilities were determined! If you have any more questions, feel free to ask.

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