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The director of health services is concerned about a possible flu outbreak at her college. She surveyed 100 randomly selected residents from the college's dormitories to see whether they had received a preventative flu shot. The results are shown below.

What is the probability that a dormitory resident chosen at random from this group has had a flu shot, given that he is male?

Residents At College Dormitories

[tex]
\[
\begin{tabular}{|c|c|c|c|}
\hline
& Male & Female & Total \\
\hline
Had Flu Shot & 39 & 41 & 80 \\
\hline
\begin{tabular}{c}
Didn't Have \\
Flu Shot
\end{tabular}
& 12 & 8 & 20 \\
\hline
Total & 51 & 49 & 100 \\
\hline
\end{tabular}
\]
[/tex]

A. [tex]\(\frac{39}{100}\)[/tex]

B. [tex]\(\frac{13}{17}\)[/tex]

C. [tex]\(\frac{51}{100}\)[/tex]

D. [tex]\(\frac{39}{80}\)[/tex]

Answer :

To solve this problem, we need to find the probability that a dormitory resident chosen at random is male and has had a flu shot.

Here is how we can approach it step-by-step:

1. Identify the total number of males surveyed: According to the data provided, the total number of male residents surveyed is 51.

2. Identify the number of males who have had a flu shot: The data also tells us that 39 males have had a flu shot.

3. Compute the probability: To find the probability that a randomly chosen male has had a flu shot, we need to divide the number of males who have had the flu shot by the total number of males surveyed.

Mathematically, this can be expressed as:

[tex]\[
\text{Probability} = \frac{\text{Number of males who had a flu shot}}{\text{Total number of males}}
\][/tex]

Substituting the values we have:

[tex]\[
\text{Probability} = \frac{39}{51}
\][/tex]

4. Calculate the result: Simplifying [tex]\(\frac{39}{51}\)[/tex] gives us approximately 0.765.

So, the probability that a dormitory resident chosen at random from this group has had a flu shot, given that he is male, is approximately 0.765 or [tex]\(\frac{13}{17}\)[/tex] when expressed as a fraction.

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Rewritten by : Barada