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Select the correct answer from each drop-down menu.

If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a [tex]\checkmark[/tex] chance that the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Answer :

Certainly! Let's take a closer look at the question and solve it step-by-step.

### First Part:
Problem: If a heterozygous male with the genotype Ww is mated with a homozygous recessive female (ww), what is the chance that the offspring will be heterozygous?

1. Determining Offspring Genotypes:
- The male (Ww) can pass on either W or w alleles.
- The female (ww) can pass on only w alleles.

2. Creating the Punnett Square:
- Write the possible alleles from each parent:
```
Male: W, w
Female: w, w
```

3. Punnett Square Setup:
```
| | W | w |
|---|----|----|
| w | Ww | ww |
| w | Ww | ww |
```

4. Probability Calculation:
- From the Punnett square, the combinations are:
- Ww
- Ww
- ww
- ww
- Out of these four possible outcomes, two are heterozygous (Ww).
- Thus, the probability of having a heterozygous offspring (Ww) is 2 out of 4, or 50%.

### Second Part:
Problem: If a heterozygous (Ww) is crossed with a homozygous dominant (WW), what is the probability of having a homozygous recessive offspring (ww)?

1. Determining Offspring Genotypes:
- The heterozygous parent (Ww) can pass on either W or w alleles.
- The homozygous dominant parent (WW) can pass on only W alleles.

2. Creating the Punnett Square:
- Write the possible alleles from each parent:
```
Ww: W, w
WW: W, W
```

3. Punnett Square Setup:
```
| | W | W |
|---|----|----|
| W | WW | WW |
| w | Ww | Ww |
```

4. Probability Calculation:
- The combinations from the Punnett square are:
- WW
- WW
- Ww
- Ww
- None of these combinations result in a homozygous recessive genotype (ww).
- Therefore, the probability of having a homozygous recessive offspring is 0%.

In summary, the probability of the offspring being heterozygous when mating a Ww with ww is 50%, and there is a 0% probability of having a homozygous recessive offspring when crossing Ww and WW.

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