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Answer :
We have that the workdone in stretching natural length to is mathematically given as
W=9/2lbft
Workdone in stretching natural length
Question Parameters:
- A force of 128 lb is required to hold a spring stretched 2 ft beyond its natural length.
- Stretching it from its natural length to 9 inches beyond its natural length
Generally the Hookes equation for the Force is mathematically given as
F=Kx
Where
3.2lb=2ft*k
Thereofore
k=16
Force becomes
f=kx
f=16x
Hence
[tex]W=8[x^2]^{3/4}_{0}[/tex]
W=9/2lbft
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