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Jack threw a Super Bowl party and ordered pizza and breadsticks. The breadsticks were [tex]\$4[/tex] each, and the pizza was [tex]\$11[/tex] each. John wants to spend at most [tex]\$160[/tex] if he ordered a minimum of 20 items. Which two inequalities could be used to determine how many of each food item he got?

(Select 2 answers)

A. [tex]4b + 11p \leq 160[/tex]

B. [tex]b + p < 20[/tex]

C. [tex]b + p \geq 20[/tex]

D. [tex]4b + 11p \geq 160[/tex]

E. [tex]4p + 11p \geq 160[/tex]

F. [tex]b + p \geq 20[/tex]

Answer :

Sure, let's break down the problem and solve it step-by-step.

### Problem Recap
Jack is ordering two types of items for his Superbowl party:
- Breadsticks, which cost \[tex]$4 each
- Pizzas, which cost \$[/tex]11 each

Jack wants to:
1. Spend at most \[tex]$160.
2. Order a minimum of 20 items in total.

We need to find the two inequalities that represent these conditions.

### Step-by-Step Solution

Condition 1: Budget Constraint
Jack wants to spend at most \$[/tex]160. We can represent this condition mathematically.

If:
- [tex]\( b \)[/tex] is the number of breadsticks
- [tex]\( p \)[/tex] is the number of pizzas

The total spending can be written as:
[tex]\[ 4b + 11p \leq 160 \][/tex]

This is our first inequality.

Condition 2: Minimum Number of Items
Jack also wants to order at least 20 items in total. We can write this condition as:
[tex]\[ b + p \geq 20 \][/tex]

This is our second inequality.

### Conclusion

The two inequalities that correctly represent the conditions given in the problem are:
[tex]\[ 4b + 11p \leq 160 \][/tex]
[tex]\[ b + p \geq 20 \][/tex]

Thus, the correct choices are:
- [tex]\( 4b + 11p \leq 160 \)[/tex]
- [tex]\( b + p \geq 20 \)[/tex]

These inequalities ensure that Jack sticks to his budget and orders a sufficient number of items for his party.

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