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Answer :
Sure! Let's solve this linear programming problem using the simplex method step by step to find the maximum value of [tex]\( z \)[/tex].
### Problem Statement:
Maximize [tex]\( z = x_1 + 2x_2 + x_3 + 3x_4 \)[/tex]
Subject to:
1. [tex]\( x_1 + 7x_2 + x_3 + x_4 \leq 70 \)[/tex]
2. [tex]\( 4x_1 + x_2 + 9x_3 + x_4 \leq 140 \)[/tex]
3. [tex]\( x_1, x_2, x_3, x_4 \geq 0 \)[/tex]
### Step-by-Step Solution:
Step 1: Convert to Standard Form
To use the simplex method, we first convert the inequalities into equalities by adding slack variables.
- For the first inequality: [tex]\( x_1 + 7x_2 + x_3 + x_4 + s_1 = 70 \)[/tex]
- For the second inequality: [tex]\( 4x_1 + x_2 + 9x_3 + x_4 + s_2 = 140 \)[/tex]
Now, the objective function becomes:
- Maximize [tex]\( z = x_1 + 2x_2 + x_3 + 3x_4 + 0s_1 + 0s_2 \)[/tex]
Step 2: Set Up the Initial Simplex Tableau
The initial tableau includes the coefficients of the objective function and constraints:
| Basic | [tex]\(x_1\)[/tex] | [tex]\(x_2\)[/tex] | [tex]\(x_3\)[/tex] | [tex]\(x_4\)[/tex] | [tex]\(s_1\)[/tex] | [tex]\(s_2\)[/tex] | RHS |
|-------|-------------|-------------|-------------|-------------|-------------|-------------|-----|
| [tex]\(z\)[/tex] | [tex]\(-1\)[/tex] | [tex]\(-2\)[/tex] | [tex]\(-1\)[/tex] | [tex]\(-3\)[/tex] | [tex]\(0\)[/tex] | [tex]\(0\)[/tex] | [tex]\(0\)[/tex] |
| [tex]\(s_1\)[/tex]| [tex]\(1\)[/tex] | [tex]\(7\)[/tex] | [tex]\(1\)[/tex] | [tex]\(1\)[/tex] | [tex]\(1\)[/tex] | [tex]\(0\)[/tex] | [tex]\(70\)[/tex] |
| [tex]\(s_2\)[/tex]| [tex]\(4\)[/tex] | [tex]\(1\)[/tex] | [tex]\(9\)[/tex] | [tex]\(1\)[/tex] | [tex]\(0\)[/tex] | [tex]\(1\)[/tex] | [tex]\(140\)[/tex] |
Step 3: Perform Simplex Iterations
Using the tableau, we perform iterations to find the optimal solution.
Step 4: Interpret the Result
After applying the simplex method, we find that the maximum value of [tex]\( z \)[/tex] is 210. This occurs when:
- [tex]\( x_1 = 0 \)[/tex]
- [tex]\( x_2 = 0 \)[/tex]
- [tex]\( x_3 = 0 \)[/tex]
- [tex]\( x_4 = 70 \)[/tex]
- Slack variables [tex]\( s_1 \)[/tex] and [tex]\( s_2 \)[/tex] adjust to maintain the equalities.
Conclusion:
The maximum is [tex]\( 210 \)[/tex] when [tex]\( x_1 = 0 \)[/tex], [tex]\( x_2 = 0 \)[/tex], [tex]\( x_3 = 0 \)[/tex], [tex]\( x_4 = 70 \)[/tex], [tex]\( s_1 = 0 \)[/tex], and [tex]\( s_2 = 0 \)[/tex]. Therefore, the correct choice is:
A. The maximum is [tex]\( 210 \)[/tex] when [tex]\( x_1 = 0 \)[/tex], [tex]\( x_2 = 0 \)[/tex], [tex]\( x_3 = 0 \)[/tex], [tex]\( x_4 = 70 \)[/tex], [tex]\( s_1 = 0 \)[/tex], and [tex]\( s_2 = 0 \)[/tex].
### Problem Statement:
Maximize [tex]\( z = x_1 + 2x_2 + x_3 + 3x_4 \)[/tex]
Subject to:
1. [tex]\( x_1 + 7x_2 + x_3 + x_4 \leq 70 \)[/tex]
2. [tex]\( 4x_1 + x_2 + 9x_3 + x_4 \leq 140 \)[/tex]
3. [tex]\( x_1, x_2, x_3, x_4 \geq 0 \)[/tex]
### Step-by-Step Solution:
Step 1: Convert to Standard Form
To use the simplex method, we first convert the inequalities into equalities by adding slack variables.
- For the first inequality: [tex]\( x_1 + 7x_2 + x_3 + x_4 + s_1 = 70 \)[/tex]
- For the second inequality: [tex]\( 4x_1 + x_2 + 9x_3 + x_4 + s_2 = 140 \)[/tex]
Now, the objective function becomes:
- Maximize [tex]\( z = x_1 + 2x_2 + x_3 + 3x_4 + 0s_1 + 0s_2 \)[/tex]
Step 2: Set Up the Initial Simplex Tableau
The initial tableau includes the coefficients of the objective function and constraints:
| Basic | [tex]\(x_1\)[/tex] | [tex]\(x_2\)[/tex] | [tex]\(x_3\)[/tex] | [tex]\(x_4\)[/tex] | [tex]\(s_1\)[/tex] | [tex]\(s_2\)[/tex] | RHS |
|-------|-------------|-------------|-------------|-------------|-------------|-------------|-----|
| [tex]\(z\)[/tex] | [tex]\(-1\)[/tex] | [tex]\(-2\)[/tex] | [tex]\(-1\)[/tex] | [tex]\(-3\)[/tex] | [tex]\(0\)[/tex] | [tex]\(0\)[/tex] | [tex]\(0\)[/tex] |
| [tex]\(s_1\)[/tex]| [tex]\(1\)[/tex] | [tex]\(7\)[/tex] | [tex]\(1\)[/tex] | [tex]\(1\)[/tex] | [tex]\(1\)[/tex] | [tex]\(0\)[/tex] | [tex]\(70\)[/tex] |
| [tex]\(s_2\)[/tex]| [tex]\(4\)[/tex] | [tex]\(1\)[/tex] | [tex]\(9\)[/tex] | [tex]\(1\)[/tex] | [tex]\(0\)[/tex] | [tex]\(1\)[/tex] | [tex]\(140\)[/tex] |
Step 3: Perform Simplex Iterations
Using the tableau, we perform iterations to find the optimal solution.
Step 4: Interpret the Result
After applying the simplex method, we find that the maximum value of [tex]\( z \)[/tex] is 210. This occurs when:
- [tex]\( x_1 = 0 \)[/tex]
- [tex]\( x_2 = 0 \)[/tex]
- [tex]\( x_3 = 0 \)[/tex]
- [tex]\( x_4 = 70 \)[/tex]
- Slack variables [tex]\( s_1 \)[/tex] and [tex]\( s_2 \)[/tex] adjust to maintain the equalities.
Conclusion:
The maximum is [tex]\( 210 \)[/tex] when [tex]\( x_1 = 0 \)[/tex], [tex]\( x_2 = 0 \)[/tex], [tex]\( x_3 = 0 \)[/tex], [tex]\( x_4 = 70 \)[/tex], [tex]\( s_1 = 0 \)[/tex], and [tex]\( s_2 = 0 \)[/tex]. Therefore, the correct choice is:
A. The maximum is [tex]\( 210 \)[/tex] when [tex]\( x_1 = 0 \)[/tex], [tex]\( x_2 = 0 \)[/tex], [tex]\( x_3 = 0 \)[/tex], [tex]\( x_4 = 70 \)[/tex], [tex]\( s_1 = 0 \)[/tex], and [tex]\( s_2 = 0 \)[/tex].
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