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Using the isotope symbol, determine the number of protons, neutrons, and electrons in this atom: [tex]{}_{82}^{207} \text{Pb}^{2+}[/tex]

Select the correct option:

A. Protons: 82 Neutrons: 207 Electrons: 82
B. Protons: 82 Neutrons: 207 Electrons: 80
C. Protons: 82 Neutrons: 125 Electrons: 82
D. Protons: 82 Neutrons: 125 Electrons: 80
E. All of the above
F. None of the above
G. There are multiple correct answers
H. Not enough information is given

Answer :

Sure! Let's break down how to determine the number of protons, neutrons, and electrons in the isotope [tex]\({ }_{82}^{207} \text{Pb}^{2+}\)[/tex].

1. Protons: The subscript number in the isotope symbol indicates the number of protons, which is also the atomic number. In [tex]\({ }_{82}^{207} \text{Pb}^{2+}\)[/tex], the subscript is 82. Therefore, this atom has 82 protons.

2. Neutrons: The mass number, which is the superscript in the isotope symbol, represents the total number of protons and neutrons combined in the nucleus. The mass number here is 207. To find the number of neutrons, subtract the number of protons from the mass number:

[tex]\[
\text{Neutrons} = \text{Mass Number} - \text{Protons} = 207 - 82 = 125
\][/tex]

3. Electrons: A neutral atom has the same number of electrons as protons. However, the symbol [tex]\(\text{Pb}^{2+}\)[/tex] indicates the atom has lost 2 electrons, making it a positive ion. Hence, the number of electrons is:

[tex]\[
\text{Electrons} = \text{Protons} - 2 = 82 - 2 = 80
\][/tex]

Thus, for the isotope [tex]\({ }_{82}^{207} \text{Pb}^{2+}\)[/tex], the numbers of particles are:
- Protons: 82
- Neutrons: 125
- Electrons: 80

This corresponds to the option: Protons: 82 Neutrons: 125 Electrons: 80.

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