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A block of mass 53.1 kg rests on a slope having an angle of elevation of 24.3°. If pushing downhill on the block with a force just exceeding 182 N and parallel to the slope is sufficient to cause the block to start moving, find the coefficient of static friction.

Answer :

Final answer:

To find the coefficient of static friction, we first need to determine the force of static friction acting on the block. The force of static friction can be calculated using the formula fs = µsN, where µs is the coefficient of static friction and N is the normal force. Using this equation and the given information, we can solve for µs.

Explanation:

To find the coefficient of static friction, we first need to determine the force of static friction acting on the block. Since the block is on an incline, the force of static friction can be calculated using the formula fs = µsN, where µs is the coefficient of static friction and N is the normal force. In this case, the normal force is equal to the weight of the block perpendicular to the slope, which is N = mgcosθ, where m is the mass of the block and θ is the angle of elevation. Since the problem states that a force just exceeding 182 N is required to move the block, we can set up an equation fs = 182 N. Substituting the expressions for fs and N, we have µs(mgcosθ) = 182 N. Solving for µs, we get µs = 182 N / (mgcosθ).

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