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Answer :
Final answer:
The effective value of g at 7000 m above the Earth's surface is approximately 9.712 m/s^2, and at 7000 km above the Earth's surface is approximately 2.216 m/s^2.
Explanation:
To calculate the effective value of g at a certain height above the Earth's surface, we can use the formula:
g' = g * (R / (R + h))^2
Where:
- g is the acceleration due to gravity at the Earth's surface (approximately 9.8 m/s^2)
- R is the radius of the Earth (approximately 6,371 km)
- h is the height above the Earth's surface
Let's calculate the effective value of g at 7000 m:
g' = 9.8 * (6371000 / (6371000 + 7000))^2
g' = 9.8 * (6371000 / 6378000)^2
g' = 9.8 * 0.997^2
g' ≈ 9.8 * 0.994 = 9.712 m/s^2
Therefore, the effective value of g at 7000 m above the Earth's surface is approximately 9.712 m/s^2.
Now, let's calculate the effective value of g at 7000 km:
g' = 9.8 * (6371000 / (6371000 + 7000000))^2
g' = 9.8 * (6371000 / 13371000)^2
g' = 9.8 * 0.476^2
g' ≈ 9.8 * 0.227 = 2.216 m/s^2
Therefore, the effective value of g at 7000 km above the Earth's surface is approximately 2.216 m/s^2.
Learn more about calculating the effective value of g at different heights above the earth's surface here:
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