We appreciate your visit to A sample of tex NO 2 tex at 857 4 K experiences a change in volume from 97 3 L to 83 32 L If. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To find the original pressure, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas before and after a change under the same number of moles. The formula for the combined gas law is:
[tex]\[
\frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2}
\][/tex]
Here, [tex]\( P_1 \)[/tex] is the initial pressure (which we are trying to find), [tex]\( V_1 \)[/tex] is the initial volume, [tex]\( T_1 \)[/tex] is the initial temperature, [tex]\( P_2 \)[/tex] is the final pressure, [tex]\( V_2 \)[/tex] is the final volume, and [tex]\( T_2 \)[/tex] is the final temperature.
Let's plug in the given values:
- [tex]\( V_1 = 97.3 \)[/tex] L
- [tex]\( V_2 = 83.32 \)[/tex] L
- [tex]\( T_1 = 857.4 \)[/tex] K
- [tex]\( T_2 = 892.1 \)[/tex] K
- [tex]\( P_2 = 6.4209 \)[/tex] atm
We need to solve for [tex]\( P_1 \)[/tex]. Rearrange the formula to solve for [tex]\( P_1 \)[/tex]:
[tex]\[
P_1 = \frac{P_2 \times V_2 \times T_1}{V_1 \times T_2}
\][/tex]
Substitute the values into the equation:
[tex]\[
P_1 = \frac{6.4209 \times 83.32 \times 857.4}{97.3 \times 892.1}
\][/tex]
After performing the calculation, we find that:
[tex]\[
P_1 \approx 5.284
\][/tex]
Thus, the original pressure of the gas was approximately 5.284 atm.
[tex]\[
\frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2}
\][/tex]
Here, [tex]\( P_1 \)[/tex] is the initial pressure (which we are trying to find), [tex]\( V_1 \)[/tex] is the initial volume, [tex]\( T_1 \)[/tex] is the initial temperature, [tex]\( P_2 \)[/tex] is the final pressure, [tex]\( V_2 \)[/tex] is the final volume, and [tex]\( T_2 \)[/tex] is the final temperature.
Let's plug in the given values:
- [tex]\( V_1 = 97.3 \)[/tex] L
- [tex]\( V_2 = 83.32 \)[/tex] L
- [tex]\( T_1 = 857.4 \)[/tex] K
- [tex]\( T_2 = 892.1 \)[/tex] K
- [tex]\( P_2 = 6.4209 \)[/tex] atm
We need to solve for [tex]\( P_1 \)[/tex]. Rearrange the formula to solve for [tex]\( P_1 \)[/tex]:
[tex]\[
P_1 = \frac{P_2 \times V_2 \times T_1}{V_1 \times T_2}
\][/tex]
Substitute the values into the equation:
[tex]\[
P_1 = \frac{6.4209 \times 83.32 \times 857.4}{97.3 \times 892.1}
\][/tex]
After performing the calculation, we find that:
[tex]\[
P_1 \approx 5.284
\][/tex]
Thus, the original pressure of the gas was approximately 5.284 atm.
Thanks for taking the time to read A sample of tex NO 2 tex at 857 4 K experiences a change in volume from 97 3 L to 83 32 L If. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
