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Answer :
Average force acting on Purley is -1749m/[tex]s^{2}[/tex].
What is Newton's second law of motion?
According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is determined by multiplying its mass by its speed.
Given,
According to newton's second law of motion:
F =ma
Purley's initial speed = 173km/h
Final speed = 0
Distance traveled = 0.66 m
So, [tex]v_{i}[/tex] = 172 km/h × 1 hr/3600 s × 1000m/1km
[tex]v_{i}[/tex] = 48.1 m/s
By using kinematics
[tex]v^{2} f[/tex] = [tex]v^{2} i[/tex] + 2ad
[tex]0^{2}[/tex] = 48.[tex]1^{2}[/tex] + 2a(0.66)
-1.32a = 2309
a= -1749 m/[tex]s^{2}[/tex]
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Final answer:
Using Physics equations, you can calculate the force exerted on David Purley during the crash by first finding the deceleration rate and the time it took for the deceleration. Substituting these into the F=ma equation, you will find the average force during the crash, which is much larger than his weight.
Explanation:
In physics, we can use the formula of Newton's second law of motion (F=ma) to calculate the force exerted on David Purley during the crash. Force equals mass times acceleration, or in this case, deceleration. First, we need to convert km/h into m/s by dividing 173 by 3.6 to get 48.06 m/s. Deceleration refers to the change in velocity, which is from 48.06 m/s to 0 m/s, so the deceleration rate is -48.06 m/s. To find the time, we use the formula s=vt+0.5at^2. Then we substitute into F=ma to find the average force during the crash, which is significantly larger than his weight, demonstrating the severe impact of the crash.
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