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1. If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that offspring will be heterozygous. [tex]\square[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

2. If the heterozygous individual, Ww, is crossed with a homozygous dominant individual, WW, then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

[tex]\text{Reset}[/tex]

[tex]\text{Next}[/tex]

Answer :

To solve the problem, we need to look at two genetic crosses and determine the likelihood of certain genotypes appearing in the offspring.

### Part 1: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)

1. Parent Genotypes:
- Male: Ww (heterozygous)
- Female: ww (homozygous recessive)

2. Punnett Square for the Cross:

```
| | W | w |
|---|----|----|
| w | Ww | ww |
| w | Ww | ww |
```

3. Offspring Genotypes:
- Ww
- ww

4. Probability of Heterozygous Offspring (Ww):

Out of the four possible combinations:
- Two are Ww (heterozygous)
- Two are ww (homozygous recessive)

Therefore, the probability that an offspring is heterozygous (Ww) is 2 out of 4, which is 0.5, or 50%.

### Part 2: Cross Between Heterozygous (WW) and Homozygous Dominant (WW)

1. Parent Genotypes:
- First individual: WW (homozygous dominant)
- Second individual: Ww (heterozygous)

2. Punnett Square for the Cross:

```
| | W | w |
|---|----|----|
| W | WW | Ww |
| W | WW | Ww |
```

3. Offspring Genotypes:
- WW
- Ww

4. Probability of Homozygous Recessive Offspring (ww):

In this case, none of the offspring can be ww because at least one W will always be present in the combination.

Therefore, the probability of having a homozygous recessive (ww) offspring is 0, or 0%.

In summary, the chance of having a heterozygous offspring (Ww) in the first scenario is 50%, and the chance of having a homozygous recessive offspring (ww) in the second scenario is 0%.

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