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Answer :
To solve this problem, we need to find the outer and inner radii of a hollow right circular cylinder, given that:
1. The difference between the outer and inner radii is 1 cm.
2. The volume of the metal used to make the cylinder is 176 cm³.
3. The length (height) of the cylinder is 14 cm.
Let's solve this step by step:
### Step 1: Set up the relationship between the outer and inner radii.
Let [tex]\( r_{\text{outer}} \)[/tex] be the outer radius and [tex]\( r_{\text{inner}} \)[/tex] be the inner radius.
According to the problem, the difference between the outer and inner radii is 1 cm:
[tex]\[ r_{\text{outer}} - r_{\text{inner}} = 1 \][/tex]
### Step 2: Use the formula for the volume of a hollow cylinder.
The volume of a hollow cylinder is given by:
[tex]\[ V = \pi \times (r_{\text{outer}}^2 - r_{\text{inner}}^2) \times \text{length} \][/tex]
Given:
- Volume ([tex]\( V \)[/tex]) = 176 cm³
- Length = 14 cm
Substituting these values into the formula:
[tex]\[ 176 = \pi \times (r_{\text{outer}}^2 - r_{\text{inner}}^2) \times 14 \][/tex]
### Step 3: Solve the equations.
Using the equation from Step 1:
[tex]\[ r_{\text{outer}} = r_{\text{inner}} + 1 \][/tex]
Substitute [tex]\( r_{\text{outer}} = r_{\text{inner}} + 1 \)[/tex] into the volume formula:
[tex]\[ 176 = \pi \times ((r_{\text{inner}} + 1)^2 - r_{\text{inner}}^2) \times 14 \][/tex]
Simplify the expression:
[tex]\[ 176 = \pi \times ((r_{\text{inner}}^2 + 2r_{\text{inner}} + 1) - r_{\text{inner}}^2) \times 14 \][/tex]
[tex]\[ 176 = \pi \times (2r_{\text{inner}} + 1) \times 14 \][/tex]
Divide both sides by [tex]\( 14\pi \)[/tex]:
[tex]\[ \frac{176}{14\pi} = 2r_{\text{inner}} + 1 \][/tex]
Simplify to find [tex]\( r_{\text{inner}} \)[/tex]:
[tex]\[ r_{\text{inner}} = \frac{176}{28\pi} - \frac{1}{2} \][/tex]
Calculate the numerical values:
[tex]\[ r_{\text{inner}} \approx 1.5008 \, \text{cm} \][/tex]
Now, use [tex]\( r_{\text{outer}} = r_{\text{inner}} + 1 \)[/tex]:
[tex]\[ r_{\text{outer}} \approx 1.5008 + 1 = 2.5008 \, \text{cm} \][/tex]
### Conclusion:
- Outer radius ([tex]\( r_{\text{outer}} \)[/tex]): Approximately 2.50 cm
- Inner radius ([tex]\( r_{\text{inner}} \)[/tex]): Approximately 1.50 cm
These are the radii for the hollow right circular cylinder based on the problem's conditions.
1. The difference between the outer and inner radii is 1 cm.
2. The volume of the metal used to make the cylinder is 176 cm³.
3. The length (height) of the cylinder is 14 cm.
Let's solve this step by step:
### Step 1: Set up the relationship between the outer and inner radii.
Let [tex]\( r_{\text{outer}} \)[/tex] be the outer radius and [tex]\( r_{\text{inner}} \)[/tex] be the inner radius.
According to the problem, the difference between the outer and inner radii is 1 cm:
[tex]\[ r_{\text{outer}} - r_{\text{inner}} = 1 \][/tex]
### Step 2: Use the formula for the volume of a hollow cylinder.
The volume of a hollow cylinder is given by:
[tex]\[ V = \pi \times (r_{\text{outer}}^2 - r_{\text{inner}}^2) \times \text{length} \][/tex]
Given:
- Volume ([tex]\( V \)[/tex]) = 176 cm³
- Length = 14 cm
Substituting these values into the formula:
[tex]\[ 176 = \pi \times (r_{\text{outer}}^2 - r_{\text{inner}}^2) \times 14 \][/tex]
### Step 3: Solve the equations.
Using the equation from Step 1:
[tex]\[ r_{\text{outer}} = r_{\text{inner}} + 1 \][/tex]
Substitute [tex]\( r_{\text{outer}} = r_{\text{inner}} + 1 \)[/tex] into the volume formula:
[tex]\[ 176 = \pi \times ((r_{\text{inner}} + 1)^2 - r_{\text{inner}}^2) \times 14 \][/tex]
Simplify the expression:
[tex]\[ 176 = \pi \times ((r_{\text{inner}}^2 + 2r_{\text{inner}} + 1) - r_{\text{inner}}^2) \times 14 \][/tex]
[tex]\[ 176 = \pi \times (2r_{\text{inner}} + 1) \times 14 \][/tex]
Divide both sides by [tex]\( 14\pi \)[/tex]:
[tex]\[ \frac{176}{14\pi} = 2r_{\text{inner}} + 1 \][/tex]
Simplify to find [tex]\( r_{\text{inner}} \)[/tex]:
[tex]\[ r_{\text{inner}} = \frac{176}{28\pi} - \frac{1}{2} \][/tex]
Calculate the numerical values:
[tex]\[ r_{\text{inner}} \approx 1.5008 \, \text{cm} \][/tex]
Now, use [tex]\( r_{\text{outer}} = r_{\text{inner}} + 1 \)[/tex]:
[tex]\[ r_{\text{outer}} \approx 1.5008 + 1 = 2.5008 \, \text{cm} \][/tex]
### Conclusion:
- Outer radius ([tex]\( r_{\text{outer}} \)[/tex]): Approximately 2.50 cm
- Inner radius ([tex]\( r_{\text{inner}} \)[/tex]): Approximately 1.50 cm
These are the radii for the hollow right circular cylinder based on the problem's conditions.
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