Answer :

To find the molarity of the NaOH solution, we need to follow these steps:

1. Calculate the molar mass of NaOH:
- Sodium (Na) has an atomic mass of approximately 22.99 g/mol.
- Oxygen (O) has an atomic mass of approximately 15.999 g/mol.
- Hydrogen (H) has an atomic mass of approximately 1.008 g/mol.
- Adding these together gives us the molar mass of NaOH:
[tex]\[
22.99 + 15.999 + 1.008 = 39.997 \, \text{g/mol}
\][/tex]

2. Determine the number of moles of NaOH:
- We have 6.00 grams of NaOH.
- To find the number of moles, we use the formula:
[tex]\[
\text{moles of NaOH} = \frac{\text{mass of NaOH}}{\text{molar mass of NaOH}}
\][/tex]
- Substitute the known values:
[tex]\[
\text{moles of NaOH} = \frac{6.00 \, \text{g}}{39.997 \, \text{g/mol}} \approx 0.150 \, \text{moles}
\][/tex]

3. Calculate the molarity of the NaOH solution:
- Molarity is defined as the number of moles of solute per liter of solution.
- Using the formula:
[tex]\[
\text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}}
\][/tex]
- Here, the volume of the solution is 0.500 liters.
- Substitute the values:
[tex]\[
\text{Molarity} = \frac{0.150 \, \text{moles}}{0.500 \, \text{liters}} \approx 0.300 \, \text{M}
\][/tex]

Therefore, the molarity of the NaOH solution is approximately 0.300 M.

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Rewritten by : Barada