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Which reaction below represents the second ionization of Sr?

A. Sr(g) → Sr⁺(g) + e⁻
B. Sr²⁺(g) + e⁻ → Sr⁺(g)
C. Sr⁺(g) + e⁻ → Sr(g)
D. Sr⁻(g) + e⁻ → Sr²⁻(g)
E. Sr⁺(g) → Sr²⁺(g) + e⁻

Answer :

Answer:

[tex]Sr^{+} (g)-->Sr^{2+} (g)+e[/tex]

Explanation:

Ionization is removal of most loosely bound electron from an isolated gaseous atom.

First ionization is the removal from a neutral atom.

The equation for it is

a) [tex]Sr(g)-->Sr^{+} (g)+e[/tex]

Second ionization is the removal from a monopositive ion of the atom.

The equation is:

[tex]Sr^{+} (g)-->Sr^{2+} (g)+e[/tex]

In ionization there is no addition of electron thus all other equations are cannot be correct.

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Rewritten by : Barada

e.sr⁺(g) → sr2⁺(g) + e⁻
When remove first electron became Sr
⁺, second Sr²⁺.