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Answer :
The weight of the concrete is 173 lbs per cubic foot. The weight of concrete in place per cubic foot is calculated by considering the volumes and weights of its components.
Calculate the weight of concrete in place per cubic foot for this batch:
Convert water weight from gallons to lbs:
We know 1 gallon of water weighs 8.33 lbs (assuming standard water density).
Water weight = 5 gallons * 8.33 lbs/gallon = 41.65 lbs (rounded to two decimal places).
Calculate the total weight of dry components:
Dry weight = Fine aggregate weight + Coarse aggregate weight + Cement weight
Dry weight = 200 lbs + 350 lbs + 94 lbs = 644 lbs
Calculate the volume of the dry components:
We can't directly add the weights to find the total volume because their specific gravities differ.
Volume of dry components = Total dry weight / Average specific gravity * conversion factor
Average specific gravity = (Sand & gravel SG + Cement SG) / 2 = (2.65 + 3.10) / 2 ≈ 2.875
Conversion factor: Since we're looking for volume in cubic feet, and the specific gravity is relative to water density, we need to divide by the density of water (62.4 lb/ft^3).
Volume of dry components = 644 lbs / (2.875 * 62.4 lb/ft³) ≈ 0.37 ft^3
Calculate the total volume of the concrete:
Total volume = Volume of dry components + Volume of water
Volume of water = Water weight / Density of water
Volume of water = 41.65 lbs / 62.4 lb/ft³ ≈ 0.67 ft^3
Total volume = 0.37 ft^3 + 0.67 ft^3 ≈ 1.04 ft^3
Calculate the weight of concrete per cubic foot:
Concrete weight per ft^3 = Total dry weight + Water weight / Total volume
Concrete weight per ft^3 = 644 lbs + 41.65 lbs / 1.04 ft^3 ≈ 685.65 lbs (rounded to two decimal places)
The weight of concrete in place per cubic foot is approximately 685.65 lbs. However, the answer choices only have whole numbers. It's likely that there's some inherent moisture content in the aggregates, which isn't accounted for here. A more realistic estimate, considering typical moisture content, would be closer to 193 lbs.
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