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Answer :
We can evaluate each logarithm by using the logarithm property that states:
[tex]$$
\log_b (b^x) = x.
$$[/tex]
Let's go through each part step-by-step.
(a) Evaluate [tex]$\log_6 6^8$[/tex].
Since the base of the logarithm is the same as the base of the exponent, we have:
[tex]$$
\log_6 6^8 = 8.
$$[/tex]
(b) Evaluate [tex]$\log_3 27$[/tex].
Notice that [tex]$27$[/tex] can be written as [tex]$3^3$[/tex], so:
[tex]$$
\log_3 27 = \log_3 (3^3) = 3.
$$[/tex]
(c) Evaluate [tex]$\log_5 3125$[/tex].
Similarly, [tex]$3125$[/tex] can be expressed as [tex]$5^5$[/tex], hence:
[tex]$$
\log_5 3125 = \log_5 (5^5) = 5.
$$[/tex]
(d) Evaluate [tex]$\log_7 7^{15}$[/tex].
Again, using the logarithm property:
[tex]$$
\log_7 7^{15} = 15.
$$[/tex]
Thus, the final answers are:
- (a) [tex]$\log_6 6^8 = 8$[/tex],
- (b) [tex]$\log_3 27 = 3$[/tex],
- (c) [tex]$\log_5 3125 = 5$[/tex], and
- (d) [tex]$\log_7 7^{15} = 15$[/tex].
[tex]$$
\log_b (b^x) = x.
$$[/tex]
Let's go through each part step-by-step.
(a) Evaluate [tex]$\log_6 6^8$[/tex].
Since the base of the logarithm is the same as the base of the exponent, we have:
[tex]$$
\log_6 6^8 = 8.
$$[/tex]
(b) Evaluate [tex]$\log_3 27$[/tex].
Notice that [tex]$27$[/tex] can be written as [tex]$3^3$[/tex], so:
[tex]$$
\log_3 27 = \log_3 (3^3) = 3.
$$[/tex]
(c) Evaluate [tex]$\log_5 3125$[/tex].
Similarly, [tex]$3125$[/tex] can be expressed as [tex]$5^5$[/tex], hence:
[tex]$$
\log_5 3125 = \log_5 (5^5) = 5.
$$[/tex]
(d) Evaluate [tex]$\log_7 7^{15}$[/tex].
Again, using the logarithm property:
[tex]$$
\log_7 7^{15} = 15.
$$[/tex]
Thus, the final answers are:
- (a) [tex]$\log_6 6^8 = 8$[/tex],
- (b) [tex]$\log_3 27 = 3$[/tex],
- (c) [tex]$\log_5 3125 = 5$[/tex], and
- (d) [tex]$\log_7 7^{15} = 15$[/tex].
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