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A store sells both cold and hot beverages. Cold beverages, [tex]c[/tex], cost [tex]\$1.50[/tex], while hot beverages, [tex]h[/tex], cost [tex]\$2.00[/tex]. On Saturday, drink receipts totaled [tex]\$360[/tex], and 4 times as many cold beverages were sold as hot beverages.

Which system of linear equations represents the beverage sales on Saturday?

A. [tex]4c = h[/tex]

B. [tex]1.5c + 2h = 380[/tex]

C. [tex]c = 4h[/tex]

D. [tex]1.5c + 2h = 360[/tex]

E. [tex]c + h = 360[/tex]

F. [tex]1.5c = 4(2h)[/tex]

G. [tex]c + h = 360[/tex]

H. [tex]4(1.5c) = 2h[/tex]

Answer :

To solve the problem of determining the correct system of linear equations representing the beverage sales on Saturday, let's break down the information given:

1. Cost of Beverages:
- Cold beverages, denoted as [tex]\( c \)[/tex], cost [tex]$1.50 each.
- Hot beverages, denoted as \( h \), cost $[/tex]2.00 each.

2. Sales Information:
- The total amount of money made from selling beverages was [tex]$360.
- Four times as many cold beverages were sold as hot beverages.

Now, let's translate this information into a system of equations:

- Equation 1 (Relationship between beverages):
Since four times as many cold beverages were sold as hot beverages, we can represent this relationship as:
\[
c = 4h
\]

- Equation 2 (Total sales equation):
The total sales from both cold and hot beverages amount to $[/tex]360. So, the equation representing the total cost of beverages sold is:
[tex]\[
1.5c + 2h = 360
\][/tex]
This equation accounts for the total revenue from the cold drinks ([tex]\(1.5c\)[/tex]) and hot drinks ([tex]\(2h\)[/tex]).

Thus, the correct system of linear equations that represents the beverage sales on Saturday is:
- [tex]\( c = 4h \)[/tex]
- [tex]\( 1.5c + 2h = 360 \)[/tex]

These equations together correctly model the scenario given in the problem.

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