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Answer :
Answer: x+6 and x+7
Step-by-step explanation:
[tex]x^{2} +13x + 42 = 0\\D = b^{2} - 4ac = 169 - 4*42 = 169 - 168 = 1\\x_{1} = (-13 + 1)/2 = -6\\x_{2} = (-13 -1)/2 = -7\\\\So, x^{2} + 13x + 42 = (x+6)(x+7) \\\\\\[/tex]
Hence, the possible dimensions are x+6 and x+7.
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Answer: (x + 6) and (x + 7)
Step-by-step explanation: Determine if the polynomial terms contain a common factor. In this case, there's no common factor. Next, find two numbers whose product is 42 and whose sum is 13. The only pair of numbers that satisfies these conditions is 6 and 7. Finally, write the polynomial in factored form as (x + 6)(x + 7). Therefore, the possible dimensions of the rectangle are (x + 6) by (x + 7).
