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Answer :
Final answer:
The pressure exerted by a 10-foot tall column of water at the base is approximately 624 pounds per square foot, according to the principles of hydrostatic pressure in physics.
Explanation:
The subject of this question is hydrostatic pressure, a key concept in physics. Hydrostatic pressure refers to the pressure exerted by a fluid at equilibrium at a given point within the fluid, due to the force of gravity. It increases with depth, as the weight of the fluid increases.
To calculate the hydrostatic pressure in this case, we can use the formula p = hρg where 'p' is the pressure, 'h' is the height of the fluid (in this case, the height of the column of water), 'ρ' is the density of the fluid (for water, this is typically approximately 62.4 lb/ft³), and 'g' is the acceleration due to gravity (for Earth, this is about 32.2 ft/s²).
Using the given height of 10 feet, and the known values for the density of water and gravity, the calculation would be as follows: p = (10 feet) * (62.4 lb/ft³) * (32.2 ft/s²) = 20,106.88 lb/ft². However, since the pressure of a fluid column equals the height of the column times the density of the fluid, we simplify it to just p = h * ρ. Therefore, 10 feet of water exerts a pressure of approximately 624 (Option B) pounds per square foot at the base.
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Answer:
B. 624
Step-by-step explanation:
P = ρgh
P = (62.4 lb/ft³) (10 ft)
P = 624 lb/ft²
