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Multiply: [tex](9x + 8)(3x^2 + x - 1)[/tex]

A. [tex]27x^3 + 33x^2 + 17x + 8[/tex]

B. [tex]3x^2 + 10x + 7[/tex]

C. [tex]27x^3 + 9x^2 - 8[/tex]

D. [tex]27x^3 + 33x^2 - x - 8[/tex]

Answer :

To multiply the polynomials
[tex]$$ (9x+8) \quad \text{and} \quad (3x^2+x-1), $$[/tex]
we will use the distributive property (also known as the FOIL method when applicable for binomials). Follow these steps:

1. Multiply the term [tex]$9x$[/tex] by each term in the second polynomial:

- Multiply [tex]$9x$[/tex] by [tex]$3x^2$[/tex]:
[tex]$$ 9x \cdot 3x^2 = 27x^3 $$[/tex]
- Multiply [tex]$9x$[/tex] by [tex]$x$[/tex]:
[tex]$$ 9x \cdot x = 9x^2 $$[/tex]
- Multiply [tex]$9x$[/tex] by [tex]$-1$[/tex]:
[tex]$$ 9x \cdot (-1) = -9x $$[/tex]

This gives the partial result:
[tex]$$ 27x^3 + 9x^2 - 9x. $$[/tex]

2. Multiply the constant [tex]$8$[/tex] by each term in the second polynomial:

- Multiply [tex]$8$[/tex] by [tex]$3x^2$[/tex]:
[tex]$$ 8 \cdot 3x^2 = 24x^2 $$[/tex]
- Multiply [tex]$8$[/tex] by [tex]$x$[/tex]:
[tex]$$ 8 \cdot x = 8x $$[/tex]
- Multiply [tex]$8$[/tex] by [tex]$-1$[/tex]:
[tex]$$ 8 \cdot (-1) = -8 $$[/tex]

This gives another partial result:
[tex]$$ 24x^2 + 8x - 8. $$[/tex]

3. Combine like terms from both results:

The [tex]$x^3$[/tex] term:
[tex]$$ 27x^3 $$[/tex]

The [tex]$x^2$[/tex] terms:
[tex]$$ 9x^2 + 24x^2 = 33x^2 $$[/tex]

The [tex]$x$[/tex] terms:
[tex]$$ -9x + 8x = -x $$[/tex]

And the constant term:
[tex]$$ -8 $$[/tex]

Putting it all together, we have:
[tex]$$ 27x^3 + 33x^2 - x - 8. $$[/tex]

Thus, the product of the polynomials is:
[tex]$$ \boxed{27x^3 + 33x^2 - x - 8}. $$[/tex]

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