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Answer :
Given:
Castel:
Amount of apples sold = 6
Amount of lemon sold = 4
Total = $80
Gabriella:
Amount of apple pies sold = 6
Amount of lemon sold = 5
Total = $94
Let's find the cost of one apple pie and one lemon menrigue pie.
Let x represent cost of one apple pie
Let y represent cost of one lemon meringue pie
From this situation, we have the system of equations:
6x + 4y = 80.............equation 1
6x + 5y = 94.............equation 2
Let's solve the system by elimination.
Multiply equation 1 by -1:
-1(6x + 4y) = -1(80)
-6x - 4y = -80
Add the two equations:
-6x - 4y = -80
6x + 5y = 94
___________
0 + y = 14
y = 14
Substitute 14 for y in either of the equations.
Take equation 2:
6x + 5(14) = 94
6x + 70 = 94
Subtract 70 from both sides:
6x + 70 - 70 = 94 - 70
6x = 24
Divide both sides by 6:
[tex]\begin{gathered} \frac{6x}{6}=\frac{24}{6} \\ \\ x=4 \end{gathered}[/tex]Thus, we have:
x = 4, y = 14
The cost of one apple pie is $4
The cost of one Lemon menringue is $14
ANSWER:
Cost of one apple pie = $4
Cost of one Lemon Menringue pie = $14
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