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If the 1700-lb boom AB, the 195-lb cage BCD, and the 185-lb man have centers of gravity located at points \(G_1\), \(G_2\), and \(G_3\), respectively, determine the resultant moment produced by all the weights about point A.

Answer :

The resultant moment produced by all the weights about point a is 1700 lb * g1A + 195 lb * g2A + 185 lb * g3A.

To determine the resultant moment produced by all the weights about point A, we need to calculate the moments of each weight about the point A and then sum them. The moment of a weight about a point can be calculated using the following equation:

M = W * d

where M is the moment, W is the weight, and d is the perpendicular distance from the weight to the point in question.

Let's first find the moments of the boom, cage, and man about point A:

M1 = 1700 lb * g1A

M2 = 195 lb * g2A

M3 = 185 lb * g3A

where g1A, g2A, and g3A are the distances between points g1, g2, and g3, and point A.

Now, the resultant moment can be calculated by summing all the moments:

M_resultant = M1 + M2 + M3

To learn more about weights here:

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